7(3x+2)^2(1-x)^2+(3x+2)(1-x)^3=0

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Solution for 7(3x+2)^2(1-x)^2+(3x+2)(1-x)^3=0 equation:



7(3x+2)^2(1-x)^2+(3x+2)(1-x)^3=0
We add all the numbers together, and all the variables
7(3x+2)^2(-1x+1)^2+(3x+2)(-1x+1)^3=0
We multiply parentheses ..
(-3x^2+3x-2x+2)^3+7(3x+2)^2(-1x+1)^2=0

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